28c^2+17c-3=0

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Solution for 28c^2+17c-3=0 equation:


Simplifying
28c2 + 17c + -3 = 0

Reorder the terms:
-3 + 17c + 28c2 = 0

Solving
-3 + 17c + 28c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + -4c)(1 + -7c) = 0

Subproblem 1

Set the factor '(-3 + -4c)' equal to zero and attempt to solve: Simplifying -3 + -4c = 0 Solving -3 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -4c = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -4c = 0 + 3 -4c = 0 + 3 Combine like terms: 0 + 3 = 3 -4c = 3 Divide each side by '-4'. c = -0.75 Simplifying c = -0.75

Subproblem 2

Set the factor '(1 + -7c)' equal to zero and attempt to solve: Simplifying 1 + -7c = 0 Solving 1 + -7c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -7c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -7c = 0 + -1 -7c = 0 + -1 Combine like terms: 0 + -1 = -1 -7c = -1 Divide each side by '-7'. c = 0.1428571429 Simplifying c = 0.1428571429

Solution

c = {-0.75, 0.1428571429}

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